Nota
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demostración de eje_flotante #
Eje dentro de marco rectangular.
El siguiente código demuestra cómo colocar una curva polar flotante dentro de un cuadro rectangular. Para tener una mejor idea de las curvas polares, consulte la demostración de cuadrícula curvilínea .
import numpy as np
import matplotlib.pyplot as plt
import mpl_toolkits.axisartist.angle_helper as angle_helper
from matplotlib.projections import PolarAxes
from matplotlib.transforms import Affine2D
from mpl_toolkits.axisartist import HostAxes
from mpl_toolkits.axisartist import GridHelperCurveLinear
def curvelinear_test2(fig):
"""Polar projection, but in a rectangular box."""
# see demo_curvelinear_grid.py for details
tr = Affine2D().scale(np.pi / 180., 1.) + PolarAxes.PolarTransform()
extreme_finder = angle_helper.ExtremeFinderCycle(20,
20,
lon_cycle=360,
lat_cycle=None,
lon_minmax=None,
lat_minmax=(0, np.inf),
)
grid_locator1 = angle_helper.LocatorDMS(12)
tick_formatter1 = angle_helper.FormatterDMS()
grid_helper = GridHelperCurveLinear(tr,
extreme_finder=extreme_finder,
grid_locator1=grid_locator1,
tick_formatter1=tick_formatter1
)
ax1 = fig.add_subplot(axes_class=HostAxes, grid_helper=grid_helper)
# Now creates floating axis
# floating axis whose first coordinate (theta) is fixed at 60
ax1.axis["lat"] = axis = ax1.new_floating_axis(0, 60)
axis.label.set_text(r"$\theta = 60^{\circ}$")
axis.label.set_visible(True)
# floating axis whose second coordinate (r) is fixed at 6
ax1.axis["lon"] = axis = ax1.new_floating_axis(1, 6)
axis.label.set_text(r"$r = 6$")
ax1.set_aspect(1.)
ax1.set_xlim(-5, 12)
ax1.set_ylim(-5, 10)
ax1.grid(True)
fig = plt.figure(figsize=(5, 5))
curvelinear_test2(fig)
plt.show()